write an equation for: alpha A decay of radon - 198
beta B decay of uranium - 237
plutonium - 244 undergoes gamma decay


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Respuesta :

Answer :

Alpha decay equation : [tex]^{198}_{86}Rn\rightarrow ^{194}_{84}Po+^4_2He[/tex]

Beta decay equation : [tex]^{237}_{92}U\rightarrow ^{237}_{93}Np+^0_{-1}e[/tex]

Gamma decay equation : [tex]^{244}_{94}Pu\rightarrow ^{244}_{94}Pu+^0_0\gamma[/tex]

Explanation :

  • Alpha decay : When a larger nuclei decays into smaller nuclei by releasing alpha particle. In this process, the mass number and atomic number is reduced by 4 and 2 units respectively.

       General representation of alpha decay :

       [tex]_Z^A\textrm{X}\rightarrow _{Z-2}^{A-4}Y+_2^4\alpha[/tex]

  • Beta decay : In this process, a neutron is converted into a proton and an electron. In this decay, the atomic number is increased by 1 unit.

        General representation of beta decay :

        [tex]_Z^A\textrm{X}\rightarrow _{Z+1}^{A}Y+_{-1}^0e[/tex]

  • Gamma decay : In this process, the unstable nuclei transformed into stable nuclei by releasing gamma rays. In this process, the mass number remains same.

        General representation of gamma decay :

        [tex]_Z^A\textrm{X}^*\rightarrow _Z^A\textrm{X}+_0^0\gamma[/tex]