Answer : The number of moles present in barium nitrate solution is, 0.50 moles
Solution : Given,
Molarity of barium nitrate solution = 2 M = 2 mole/L
Volume of solution = 0.25 L
Molarity : Molarity is defined as the number of moles of solute present in one liter of solution.
Formula used :
[tex]Molarity=\frac{\text{Moles of solute}}{\text{Volume of solution in liter}}[/tex]
or,
[tex]Molarity=\frac{\text{Moles of }Ba(NO_3)_2}{\text{Volume of solution in liter}}[/tex]
Now put all the given values in this formula, we get the moles of barium nitrate.
[tex]2mole/L=\frac{\text{Moles of }Ba(NO_3)_2}{0.25L}[/tex]
[tex]\text{Moles of }Ba(NO_3)_2=0.50moles[/tex]
Therefore, the number of moles present in barium nitrate solution is, 0.50 moles
