Answer : 12 moles of [tex]H_2O[/tex] will be produced.
Solution : Given,
Moles of [tex]NH_3[/tex] = 8 moles
Moles of [tex]O_2[/tex] = 14 moles
The balanced chemical reaction is,
[tex]4NH_3+7O_2\rightarrow 4NO_2+6H_2O[/tex]
From the reaction, we conclude that
As, 4 moles of [tex]NH_3[/tex] react to give 6 moles of [tex]H_2O[/tex]
So, 8 moles of [tex]NH_3[/tex] react to give [tex]\frac{6}{4}\times 8=12[/tex] moles of [tex]H_2O[/tex]
Therefore, 12 moles of [tex]H_2O[/tex] will be produced.
