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Mass box A = 10 grams; Mass box B = 5 grams; Mass box C—made of one A and one B How many boxes of B would be required to make 30 grams of C?

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Erin2626
Mass box C is 10+5. (So C is 15)

But if C was 30, how many times could you put B (5) into it?

30/5 = 6

You would need 6 boxes of B to make 30 grams of C.

Answer: Two boxes of B would be required.

Explanation: From given information, A = 10 grams and B = 5 grams

C is made up of one A and one B box.

So, mass of C = mass of A + mass of B

mass of C = 10 g + 5 g = 15 g

number of boxes of C in 30 grams will be = [tex]30g(\frac{1box}{15g})[/tex]

= 2 boxes

So, if we want to make the two boxes of C then we also have to double the number of boxes of A and B.

Hence, to make 30 grams of C, we need to take two boxes of B since each box of C requires one box of A and one box of B.

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