Hello!
A car traveling at 15 m/s starts to decelerate steadily. It comes to a complete stop in 10 seconds. What is it's acceleration ?
We have the following data:
Vi (initial velocity) = 15 m/s (starts)
Vf (final velocity) = 0 m/s (stop)
t (time) = 10 s
a (acceleration) = ? (in m/s²)
We apply the data to the formula of the hourly function of the velocity, let us see:
[tex]V_f = V_i + a*t[/tex]
[tex]0 = 15 + a*10[/tex]
[tex]- 15 = 10\:a[/tex]
[tex]10\:a = - 15[/tex]
[tex]a = \dfrac{-15}{10}[/tex]
[tex]\boxed{\boxed{a = - 1.5\:m/s^2}}\Longrightarrow(the\:car\:slows\:down)\:\:\:\:\:\:\bf\green{\checkmark}[/tex]
Answer:
The acceleration is -1.5 m/s² (decelerate)
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[tex]\bf\red{I\:Hope\:this\:helps,\:greetings ...\:Dexteright02!}[/tex]
The acceleration of the car is -1.5 m/s².
Deceleration/Acceleration: This can be defined as the rate of change of velocity. The S. unit is m/s².
Note: Deceleration is a negative of acceleration.
The Formula of acceleration is
a = (v-u)/t................. Equation 1
Where a = acceleration, v = final velocity, u = initial velocity, t = time.
From the question,
Given: v = 0 m/s ( comes to complete stop), u = 15 m/s, t = 10 seconds.
Substitute these values into equation 1
a = (0-15)/10
a = -15/10
a = -1.5 m/s²
Hence, the acceleration of the car is -1.5 m/s²
Learn more about acceleration here: https://brainly.com/question/12043464
