Answer:
D. 27x^8
Step-by-step explanation:
what is the second term of (x+3)^9???
A. x^9
B. 3x^9
C. 9x^8
D. 27x^8
this expansion can be solved using pascal triangle or
the binomial expansion can be designated with the formula usin combination rule.
n=number of terms
[tex]^{n} c_{r} P^{r} Q^{n-r}[/tex]
let n=9
r=0
P=x
Q=3
P decreases n value while Q increases
n!/(n-r)!*r!
for the first term
9!/(9-0)!0! *x^9*3^0
for the second term
9!/(9-1)!1! *x^8*3^1
9*x^8*3
D. 27x^8
