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HELP ASAP PLSSSSSSSSSSSS
The distance it takes a truck to stop can be modeled by the function in the image

d = stopping distance in feet v = initial velocity in miles per hour f = a constant related to friction

When the truck's initial velocity on dry pavement is 40 mph, its stopping distance is 138 ft. Determine the value of f, rounded to the nearest hundredth.

HELP ASAP PLSSSSSSSSSSSS The distance it takes a truck to stop can be modeled by the function in the image d stopping distance in feet v initial velocity in mil class=

Respuesta :

wegnerkolmp2741o

Answer:

f = .39

Step-by-step explanation:

d (v) = 2.15 v^2 / (64.4 f)

v = 40

d = 138

substitute these in

138 = 2.15 (40)^2 / (64.4 *f)

simplify

138 = 2.15 (*1600) / (64.4 *f)

138 = 3440 / (64.4 *f)

multiply each side by 64.4f

138 * 64.4 f = 3440

8887.2 f = 3440

divide by 8887.2

8887.2 f /8887.2= 3440/8887.2

f=.38707

to the nearest hundredth

f = .39

adioabiola

Here, we are required to determine the value of f, rounded to the nearest hundredth.

  • Since 1 mile = 5280ft.
  • and 1hour = 3600seconds
  • Therefore, 40mph = (40 × 5280)/3600 ft/s
  • therefore, v = 58.67ft/s.

Therefore, by making f the subject of the formular in the function,

  • f = 2.15v²/64.4 × d
  • therefore, f = 2.15 × (58.67)²/64.4 × 138

  • therefore, f = 0.833 ft/s²

  • Therefore, the value of f rounded off to the nearest hundredth is 0.83ft/s²

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