[tex]f(x)=2x+1;\ g(x)=x^2-7\\\\\left(\dfrac{f}{g}\right)(x)=\dfrac{f(x)}{g(x)}\\\\\boxed{\left(\dfrac{f}{g}\right)(x)=\dfrac{2x+1}{x^2-7}}[/tex]
Answer:
Value of (f/g)(x) is:
[tex]\dfrac{2x+1}{x^2-7}[/tex]
Step-by-step explanation:
f(x)=2x+1 and g(x)=x²-7
[tex](\dfrac{f}{g})(x)=\dfrac{f(x)}{g(x)}[/tex]
⇒[tex](\dfrac{f}{g})(x)=\dfrac{2x+1}{x^2-7}[/tex]
Hence, value of (f/g)(x) is:
[tex]\dfrac{2x+1}{x^2-7}[/tex]
