The loudness, L, measured in decibels (Db), of a sound intensity, I, measured in watts per square meter, is defined as where and is the least intense sound a human ear can hear. Jessica is listening to soft music at a sound intensity level of 10-9 on her computer while she does her homework. Braylee is completing her homework while listening to very loud music at a sound intensity level of 10-3 on her headphones. How many times louder is Braylee's music than Jessica's?

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nickwhite315 nickwhite315 · Answer 1 · 2018-12-19T17:08:35+01:00

Answer:

the answer is B. or 3 times louder

Step-by-step explanation:

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aquialaska aquialaska · Answer 2 · 2019-06-12T10:15:01+02:00

Answer:

The music that Braylee is listening is 3 times louder than the music Jessica is listening.

Step-by-step explanation:

Given:

Sound Intensity level of Jessica music = {tex]10^{-9}[/tex]

Sound Intensity level of Braylee music = {tex]10^{-3}[/tex]

Now we convert intensity level to loudness of music.

we know that loudness is measured as, [tex]L=10\times\,log\;\frac{I}{I_o}[/tex]

The loudness of music that Jessica is listening given by,

[tex]L_j=10\times\,log\;\frac{10^{-9}}{10^{-12}}=10\times\,log\,10^3=10\times3log\,10=30Db[/tex]

The loudness of music that Braylee is listening given by,

[tex]L_j=10\times\,log\;\frac{10^{-3}}{10^{-12}}=10\times\,log\,10^9=10\times9log\,10=90Db[/tex]

So, Number of time Braylee's music louder than Jessica's = [tex]\frac{90}{30}=3[/tex]

Therefore, The music that Braylee is listening is 3 times louder than the music Jessica is listening.