Find two consecutive even numbers such that the difference of one-half the larger and two-fifths the smaller is equal to 38

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EXPLANATION

The consecutive even numbers are
[tex]370 \: and \: 372[/tex]

EXPLANATION

Let
[tex]x[/tex]
be the first even number then, the next even number will be,

[tex]x + 2[/tex]

The difference of one-half the larger one and two-fifth the smaller one is 38 gives the equation,


[tex] \frac{1}{2} (x + 2) - \frac{2}{5} x = 38[/tex]


We multiply through with an LCM of 10 to get,



[tex] 10 \times \frac{1}{2} (x + 2) - 10 \times \frac{2}{5} x = 38 \times 10[/tex]


This simplifies to,


[tex]5(x + 2) - 4x = 380[/tex]


We expand the brackets to get,


[tex]5x + 10 - 4x = 380[/tex]

We group like terms to get,


[tex]5x - 4x = 380 - 10[/tex]



This simplifies to
[tex]x = 370[/tex]

Therefore the next even number is is
[tex]372[/tex]