Respuesta :
Answer:
We are given:
[tex]\mu = 19.6[/tex]
[tex]\sigma = 1.3[/tex]
We have to find the weight which is greater than 70% of the data.
The z value which corresponds to 70% of the area on the standard normal table is:
[tex]z(0.70) =0.52[/tex]
Now, the weight which is greater than 70% of the data is:
[tex]z=\frac{x-\mu}{\sigma}[/tex]
[tex]0.52=\frac{x-19.6}{1.3}[/tex]
[tex]0.52 \times 1.3 = x - 19.6[/tex]
[tex]x=19.6+0.676[/tex]
[tex]x=20.28[/tex] rounded to two decimal places
Therefore, the weight which is greater than 70% of the data is 20.28 lb
Answer: 1. B) 0.0611
2. B) 2.79
3. C) 433.5 and 457.4
4. D) 11.25 and 11.81
5. A) 0.6772
6. C) 0.1379
7. C) 137.8
8. D) 0.9564
9. B) 20 and 25
10. D) 20.29
Step-by-step explanation: 100% for stats quiz (please be aware that not all stats quizzes look the same!) :)