Answer: 2.04 s
Explanation:
Let the initial velocity be v, Angle of projectile be
Then the horizontal component = v cos θ = 16 m/s
Vertical component of velocity = v sin θ = 20 m/s
Time taken to reach the highest point is half the time taken for total flight.
Time for total flight,
[tex]t = \frac{2vsin \theta}{g}[/tex]
[tex] t'=\frac{vsin \theta}{g} = \frac {20 m/s}{9.8 m/s^2} = 2.04 s[/tex]
Thus, the football takes 2.04 s to rise to the highest point of its trajectory.
