Respuesta :
There are 12 numbers in the list of values shown. Of this count, there are exactly four values that are between 7.0 and 8.0 (those values are: 7.1, 7.0, 7.3, 7.5)
So the empirical probability of picking a weight between 7.0 and 8.0 is 4/12 = 1/3 = 0.333 (approx)
Answer: Choice C) 0.333
The probability of a baby being born between 7.0 and 8.0 pounds is; 0.333
We are given simulated weight results as;
8.9, 7.1, 7.0, 5.3, 6.8, 5.5, 5.3, 5.1, 7.3, 8.5, 7.5, 9.7
The number of weights here is;
N = 12 weights
Now, we want to find the probability of the weight of the babies being between 7 and 8.
The number of weights that fall between 7 and 8 are;
7.0, 7.1, 7.3 and 7.5.
Thus;
P(a baby being born between 7.0 and 8.0 pounds) = 4/12
P(a baby being born between 7.0 and 8.0 pounds) = 0.333
Read more at; https://brainly.com/question/14095092
