Answer:
roots are not real
Step-by-step explanation:
given a quadratic in standard form : ax² + bx + c = 0 : a ≠ 0
then the discriminant Δ = b² - 4ac
the value of the discriminant informs us about the nature of the roots
• If b² - 4ac > 0, then 2 real and distinct roots
• If b² - 4ac = 0, then 2 real and equal roots
• If b² - 4ac < 0, then no real roots
given 2m² + 3 = m ( subtract m from both sides )
2m² - m + 3 = 0 ← in standard form
with a = 2, b= - 1 and c = 3
b² - 4ac = (- 1)² - (4 × 2 × 3) = 1 - 24 = - 23
Since b² - 4ac < 0 the equation has no real roots
