What is the answer for:

the sum of three consecutive odd numbers, the smaller of which is equal to 2n–1.



Respuesta :

Answer:  [tex]6n + 3[/tex]

Step-by-step explanation:

Since, Here  the smaller number = 2n - 1

Since, Numbers are consecutive.

Therefore, remaining numbers are 2n - 1 + 2 , 2n - 1 + 2 + 2

= 2n +1, 2n +3

Thus, the sum of these all numbers = 2n - 1 + 2n + 1 + 2n +3

= [tex]6 n +3[/tex]    ( By equating the like terms)