the first five terms of a sequence are 7,10, 13 , 16 and 19. which of the following functions define this sequence for all integers n>or equal to 1?
A. f[n]= 3n=7
B.f[n]= 4+3n
C. f[n]= 4[3]^n-1
D.f[n]=7[3]^n-1

Respuesta :

Answer:

Option B is correct

For [tex]n\geq 1[/tex] , the function for the given sequence is defined as; [tex]f[n] = 4 +3n[/tex]

Step-by-step explanation:

An arithmetic sequence is a sequence in which the difference between each consecutive term is constant.

An explicit formula for this arithmetic sequence given by;

[tex]a_n = a+(n-1)d[/tex] where a represents first term

Since, the given sequences; 7 , 10 , 13 , 16 and 19

⇒ common difference(d) = 3 and a = 7

Since.

10 -7 = 3

13- 10 = 3  ....

The function which defined this sequence is;

[tex]f[n]=a_n = 7 +(n-1)(3)[/tex]

using distributive property:

[tex]f[n] = 7 + 3n -3[/tex]

[tex]f[n] = 4 +3n[/tex]

therefore, the function for the given sequence for all integers [tex]n\geq 1[/tex] is;  [tex]f[n] = 4 +3n[/tex]


The correct option is D) f(n) = 4 + 3n.

Step-by-step explanation:

Given :

Arithmetic Sequence -- 7,10,13,16,19

Solution :

The explicit formula of arithmetic sequence is given by,

[tex]T_n = a+(n-1)d[/tex] ------- (1)

where, common difference (d) = 10 - 7 = 3

first term (a) = 7

So from equation (1),

[tex]T_n = 7+(n-1)3 = 7+3n-3[/tex]

[tex]T_n = 4 + 3n[/tex]

Therefore, the correct option is D) f(n) = 4 + 3n.

For more information, refer the link given below

https://brainly.com/question/15412619?referrer=searchResults