Answer: 600 bushels of 10% alcohol content and 400 bushels of 15% alcohol content.
Step-by-step explanation:
Let we add x quantity of 10% of alcohol content and y quantity of 15% alcohol content for making 12% of alcohol content mixture.
Then according to the question, 10% of x + 15 % of y = 12% of 1000
⇒ 0.1x + 0.15y = 120
⇒ 10x + 15y = 1200
⇒ 2x +3y = 2400 -------- (1)
And, x + y = 1000
⇒ 2x + 2y = 2000 ---------(2)
Equation 1) - equation 2)
We get y = 400
By putting the value of y in equation 1),
⇒2x + 1200 = 2400
⇒ 2x = 1200
⇒ x = 600
Thus, he needs to mix 600 bushel of 10% of alcohol content with 400 bushels of 12% of alcohol content for getting 1000 bushels of 12% of alcohol content.
