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In the graph, the vector terminating at A represents the complex number z. The vector terminating at B represents the product of z and -2. Which graph correctly represents the product?

In the graph the vector terminating at A represents the complex number z The vector terminating at B represents the product of z and 2 Which graph correctly rep class=
In the graph the vector terminating at A represents the complex number z The vector terminating at B represents the product of z and 2 Which graph correctly rep class=
In the graph the vector terminating at A represents the complex number z The vector terminating at B represents the product of z and 2 Which graph correctly rep class=
In the graph the vector terminating at A represents the complex number z The vector terminating at B represents the product of z and 2 Which graph correctly rep class=

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wegnerkolmp2741o

Answer:

see below

Step-by-step explanation:

We are multiplying a vector by a scalar and determining which quadrant the new vector belongs to:

A = z

B = -2z

Since  z is in the second quadrant ( x is negative and y is positive)

when we multiply by -2,   B is found by multiplying z by negative 2

The first coordinate of B, the x coordinate, is a negative value times a negative value which is positive.

The second coordinate of B, which is the y value, is a negative value times a positive value which is negative.

B is in the 4th quadrant ( x is positive, y is negative)

This is the only graph that meets that requirement.

Ver imagen wegnerkolmp2741o
euden57

Answer:

The answer is the second graph

Step-by-step explanation:

1. A complex number is coumposed by a real coordinate (in the x axis) and a imaginary coordinate (in the Y axis). If we see the vector A, we can note its direction is <-1,3>  .

2. When we multiply a number by a vector, we multiply the number by each component of the vector, as follows:

       -2  *   <-1,3>  =  <2,-6>

We can note the new direction <2,-6> is represented by the second graph.

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