Which equation could have been used to create this table?
A. y = x + 3
B. y = 4x
C. y = 3x
D. y = x + 2

Answer:
y = 3x
Step-by-step explanation:
(1,3) (2,6)
The first step is to find the rate of change ( or slope)
m = (y2-y1)/(x2-x1)
m = (6-3)/(2-1)
m = 3/1
m = 3
Then we need to use the point slope form of the equation of a line
y-y1 = m(x-x1)
y-3 = 3(x-1)
Distribute the 3
y-3 = 3x-3
Add 3 to each side
y-3+3 = 3x-3+3
y = 3x
The slope-intercept form:
[tex]y=mx+b[/tex]
m - slope
b - y-intercept
The formula of a slope:
[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]
We have the points (1, 3) and (2, 6). Substitute:
[tex]m=\dfrac{6-3}{2-1}=\dfrac{3}{1}=3[/tex]
Therefore we have:
[tex]y=3x+b[/tex]
Put the coordinates of the point (1, 3) to the equation and calculate a value of b:
[tex]3=3(1)+b[/tex]
[tex]3=3+b[/tex] subtract 3 from both sides
[tex]0=b\to b=0[/tex]