A stopwatch starts while race car travels at 4 m/s from the pit area and accelerates at a uniform rate to a speed of 23 m/s in 2 s moving on a circular track of radius 527 m.

Assuming constant tangential acceleration, find

(a) the tangential acceleration, and

(b) the radial acceleration,at the instant when the speed is v = 16

Once you have both of those ... find the magnitude of a at any moment

Respuesta :

(a) Tangential acceleration: [tex]9.5 m/s^2[/tex]

The tangential acceleration is given by:

[tex]a_t = \frac{v-u}{t}[/tex]

where

v = 23 m/s is the final velocity of the car

u = 4 m/s is the initial velocity of the car

t = 2 s is the time taken for the car to accelerate from u to v

Substituting the numbers into the formula, we find

[tex]a_t = \frac{23 m/s-4 m/s}{2 s}=9.5 m/s^2[/tex]


(b) Radial acceleration: [tex]0.49 m/s^2[/tex]

The radial acceleration is equivalent to the centripetal acceleration, which is given by:

[tex]a_r = \frac{v^2}{r}[/tex]

where

v = 16 m/s is the tangential speed

r = 527 m is the radius of the circular orbit

Substituting numbers, we find

[tex]a_r = \frac{(16 m/s)^2}{527 m}=0.49 m/s^2[/tex]