Answer:
The correct answer option is a. 14∑1 (-28+3n)
Step-by-step explanation:
The summation notation for the given series is 14∑1 (-28+3n) where [tex]i[/tex] (the index of summation or the lower limit of summation) is 1 and [tex]n[/tex] (the upper limit of summation) is 14.
Putting in the values of the limit from 1 to 14 in the notation to get the first 14 terms of the series:
[tex]-28+3(1)=-25\\\\-28+3(2)=-22\\\\-28+3(3)=-19\\\\-28+3(4)=-16\\\\-28+3(5)=-13\\\\-28+3(6)=-10\\\\-28+3(7)=-7\\\\-28+3(8)=-4\\\\-28+3(9)=-1\\\\-28+3(10)=2\\\\-28+3(11)=5\\\\-28+3(12)=8\\\\-28+3(13)=11\\\\-28+3(14)=14\\[/tex]
Therefore, first option is the correct one.
