The answer is A. A circle is inscribed in a regular hexagon with side length 10 feet. What is the area of the shaded region?

Recall that in a 30 – 60 – 90 triangle, if the shortest leg measures x units, then the longer leg measures x√3 units and the hypotenuse measures 2x units.


(150√3 - 75π) ft^2

(300 – 75π) ft^2

(150√3 – 25π) ft^2

(300 – 25π) ft^2

The answer is A A circle is inscribed in a regular hexagon with side length 10 feet What is the area of the shaded regionRecall that in a 30 60 90 triangle if t class=

Respuesta :

Answer: its A

(150 – 75π) ft2



Answer:

Option A. (150√3- 75π) ft².

Step-by-step explanation:

In the given picture a circle is inscribed in a regular hexagon with a side length = 10 feet.

Formula of the area of a regular hexagon [tex]=3\frac{\sqrt{3} }{2}(side)^{2}[/tex]

                                                              = [tex]=3\frac{\sqrt{3} }{2}(10^{2})[/tex]

                                                             = 3√3×50 = 150×√3 feet²

Now we will calculate the area of circle inscribed.

Already given in the question that In a 30-60-90 triangle

Longer leg of triangle r = x√3 = [tex]\frac{10}{2}\sqrt{3}[/tex] = 5√3 feet

Now area of circle = π r² = π(5√3)² = 75π feet²

Area of shaded part = Area of Hexagon-Area of circle inscribed.

                                 = (150√3 - 75π) ft²