For this case we must factor the following expression: [tex]6x ^ 2-9x-6[/tex]
We test the options:
Option A:
[tex]3 (2x + 1) (x-2) =[/tex]
We apply distributive property for the first parenthesis:
[tex](6x + 3) (x-2) =[/tex]
We apply distributive property of the form:
[tex](a + b) (c + d) = ac + ad + bc + bd[/tex]
[tex]6x ^ 2-12x + 3x-6 =[/tex]
Different signs are added and the sign of the major is placed.
[tex]6x ^ 2-9x-6[/tex]
So, [tex]3 (2x + 1) (x-2) = 6x ^ 2-9x-6[/tex]
Answer:
Option A
