Respuesta :
Answer: Y= -3/4x+13
Step-by-step explanation:
A line passes through the point (8,7) and has a slope of negative 3/4 Write an equation in slope-intercept form for this line.
This is what i get
Slope of a line Y= mx+b
Y= 7
X= 8
M= -3/4
7= -3/4(8)+b
7= -6+b
7+6=b
13=b
Y= -3/4x+13
The equation in slope-intercept form for this line is y = (-3/4) x + 13
What is the equation for a straight line ?
The equation for a straight line is given by y = mx + c
where m is the slope , and c is the intercept on y axis.
For two points given
m = (y₂-y₁)/(x₂-x₁)
It is given in the question that
A line passes through the point (8,7) and has a slope of negative 3/4
The value of the intercept needs to be determined and that can be determined using the data given
At x = 8 , y = 7 , m = - 3 / 4
Substituting the values
7 = (-3/4) * 8 + c
7 = -6 + c
13 = c
Therefore now as all the values are known
The equation is
y = (-3/4) x + 13
The equation in slope-intercept form for this line is y = (-3/4) x + 13.
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