Answer:
h[j(2)] =-13
Step-by-step explanation:
The first step is to solve j(2) by putting x=2 into j(x)
j(2) = -2(2) = -4
Now we put x= -4 into h(x)
h(-4) = 3(-4) -1
h(-4) = -12-1 = -13
h[j(2)] =-13
Answer:
h[j(2)] = -13.
Step-by-step explanation:
Given : If h(x) = 3x − 1 and j(x) = −2x,
To find : solve h[j(2)] .
Solution : We have given
h(x) = 3x − 1 and j(x) = −2x
For x = 2 ,
j (2) = -2 (2).
j(2) = -4 .
h[j(2)] = h(-4) .
h(4) = 3 (-4) -1 .
h(4) = -12 -1 .
h[j(2)] = h(4) = -13.
h[j(2)] = -13.
Therefore, h[j(2)] = -13.
