Hello from MrBillDoesMath!
Answer:
There is no p value that answers the question.
Discussion:
Consider the quadratic ax^2 + b^x + c = 0. The solution is
x = ( -b +\- sqrt(b^2-4ac)) /2a
If b^2-4ac is NOT zero then there are two values of x that solve the equation. In b^2-4ac = 0, then both roots are equal, so there is only one solution.
Taking a = 2, b = p, and c = -6, in the quadratic formula:
b^2 - 4ac = 0 => ( again, = 0 for a single root)
p^2 - 4(2)(-6) = 0 =>
p^2 + 48 = 0 =>
which has no real solution as p^2 >= 0, so p^2 +48 >= 48 which means that p^2 + 48 =0 is not possible
Regards,
MrB
