point a has the coordinates(2,5) point B has the coordinates (6,17) how long is segment ab in simplified radical form

Respuesta :

Answer:

[tex]4\sqrt{10}[/tex]

Step-by-step explanation:

We have been given that point A has the coordinates(2,5) point B has the coordinates (6,17).

To find the length of segment AB we will use distance formula.

[tex]\text{Distance}=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Upon substituting coordinates of point A and point B in distance formula we will get,

[tex]\text{Distance between point A and point B}=\sqrt{(6-2)^2+(17-5)^2}[/tex]

[tex]\text{Distance between point A and point B}=\sqrt{(4)^2+(12)^2}[/tex]

[tex]\text{Distance between point A and point B}=\sqrt{16+144}[/tex]

[tex]\text{Distance between point A and point B}=\sqrt{160}[/tex]

[tex]\text{Distance between point A and point B}=4\sqrt{10}[/tex]

Therefore, the length of segment AB is [tex]4\sqrt{10}[/tex].