From a boat on the lake, the angle of elevation to the top of a cliff is 28°16'. If the base of the cliff is 1307 ft from the boat, how high is the cliff (to the nearest foot)
keeping in mind that there are 60 minutes in 1 degree, thus 16' is really 16/60 ≈ 0.2666...., meaning [tex]\bf 28^o16'\implies 28.\overline{27}~^o[/tex].
