Chapman’s brickyard sells bricks and blocks. A brick costs $0.38 and a block costs $1.56. The brickyard filled a $24.80 order, which contained 28 items

a. Write a system of equations that can be used to find the number of bricks and blocks in the order.

b. How many blocks were in the order?

Respuesta :

Answer:

(a) A system of equations:

[tex]0.38x+1.56y = 24.80[/tex]  

[tex]x+y = 28[/tex]

(b) Number of blocks were in the order is, 12

Step-by-step explanation:

(a)

Let x represents the number of bricks and y represents the number of blocks.

As per the given statement:

A bricks costs $ 0.38 and a block costs $1.56.

Total  bricks costs = 0.38x and total block costs = 1.56y

The brickyard filled $24.80 order.

⇒ [tex]0.38x+1.56y = 24.80[/tex]                          ......[1]

Since, it contained 28 items.

[tex]x+y = 28[/tex]                                               ....[2]

Multiply equation [2] both sides by 0.38 we have;

[tex]0.38(x+y) = 0.38 \times 28[/tex]

Using distributive property: [tex]a\cdot (b+c) = a\cdot b + a\cdot c[/tex]

0.38x +0.38 y = 10.64                                        ......[3]

Subtract equation [3] from [1] to get x eliminated ;

[tex]0.38x+1.56y -0.38x -0.38y= 24.80 - 10.64[/tex]  

Combine like terms;

1.18y =14.16

Divide both sides by 1.18 we have;

[tex]\frac{1.18y}{1.18} = \frac{14.16}{1.18}[/tex]

Simplify:

[tex]y = 12[/tex]

Substitutes this y value in equation [2] to solve for x;

x + 12= 28

Subtract 12 from both sides we get;

x +12-12 =28-12

Simplify:

x = 16

Therefore, a system of equations that can be used to find the number of bricks and the number of blocks in the order:

[tex]0.38x+1.56y = 24.80[/tex]  

[tex]x+y = 28[/tex]

(b)

The number of blocks are in order(y), is  12.