In an effort to control vegetation overgrowth, 139 139 rabbits are released in an isolated area free of predators. After 2 2 years, it is estimated that the rabbit population has increased to 556 556 . Assuming exponential population growth, what will the population be after another 6 6 months? Round to the nearest rabbit.

Respuesta :

Answer:

197

Step-by-step explanation:

Initial population of rabbit is 139

after 2 years , rabbit population is 556

For exponential growth use y=ab^x

where a is the initial population

x is the time period

b is the growth rate, y is the final population

a= 139 is already given

when x=2, the value of y = 557

plug in all the values  in the formula and find out 'b'  

[tex]y=ab^x[/tex]

[tex]557=139(b)^2[/tex]

Divide both sides by 139

[tex]\frac{557}{139} =b^2[/tex]

take square root on both sides

b=2.00180 and b=-2.00180

growth factor cannot be negative

So b= 2.0018

The equation y=ab^x  becomes

[tex]y=139(2.0018)^x[/tex]

To find population after 6 months

1 year = 12 months

so 6 months = 0.5 years

we plug in 0.5 for x

[tex]y=139(2.0018)^{0.5}[/tex]

y= 196.66

so population after 6 months = 197