Answer:
21.5 km
Step-by-step explanation:
We have to find the distance between two boat
We are given that
AC=2.1 km
BC=3.5 km
We have to find BC
The angle between two boat =110 degrees
Using cosine law
BC=[tex]\sqrt{(2.1)^2+(3.5)^2-2\cdot(2.1)\cdot(3.5)cos 110}[/tex]
BC=[tex]\sqrt{4.41+12.25+ 2\cdot2.1\times3.5cos 70[/tex]
BC=[tex]\sqrt{4.41+12.25+9.3051}[/tex]
BC=21.507 km
Hence, the distance between two boat is 21.5 km
