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Line j passes through points (6, 14) and (9, 9).Line K is parallel to line J. What is the the slope of line K?

Respuesta :

CharlieBrown2002

Hi there! :)

Step-by-step explanation:

[tex]Slope=\frac{Y_2-Y_1}{X_2-X_1}=\frac{RISE}{RUN}[/tex]

[tex]\frac{9-14}{9-6}=\frac{-5}{3}[/tex]

Therefore, the slope is -5/3.

Final answer is -5/3.

I hope this helps you!

Have a nice day! :)

-Charlie

:D

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