Answer:
Price of floor seat =$ 17 and
Price of stadium seats = $8.5
Step-by-step explanation:
Let x represents the cost of floor seats and y represents the cost of stadium seats.
Then, from the given condition, we have;
Total cost for selling floor seats = 62x and the total cost for stadium seats = 120y.
Since, a math club earn $2,080.
⇒ 62x + 120y = 2080 .....[1]
Also, it is given that the floor seats cost twice as much as Stadium seats.
⇒ x = 2y .....[2]
Substitute this equation [2] in [1] we get;
[tex]62(2y) + 120y = 2080[/tex]
Simplify:
124y + 120y =2080
Combine like terms;
244y =2080
Divide both sides by 144 we get;
[tex]y = \frac{2080}{144} = 8.5[/tex]
⇒y = $8.5
Substitute this in [2] we get x;
x = 2(8.5) = 17
i.e, x = $ 17
Therefore, the price of floor seat is, $ 17 and the price of stadium seats is, $8.5
