Answer: 2054.86 kJ
Explanation:
Given: 2.2 lbs = 1.0 kg
[tex]2.0lbs=\frac{1.0}{2.2}\times {2.0}=0.91kg=910 g[/tex]
[tex]Q= n\times \Delta H[/tex]
Q= heat gained
n = [tex]\text{no of moles}=\frac{\text{given mass}}{\text{Molecular mass}}[/tex]
n =no of moles = [tex]\frac{910g}{18g/mol}}=50.55moles[/tex]
[tex]\Delta H[/tex] = enthalpy of vaporization of water = 40.65 kJ/mol
[tex]Q=50.55moles\times 40.65kJ/mol=2054.86kJ[/tex]
