Answer:
see explanation
Step-by-step explanation:
the equation of a line in slope- intercept form is
y = mx + b ( m is the slope and b the y-intercept )
here m = [tex]\frac{1}{3}[/tex] and b = 13, hence
y = [tex]\frac{1}{3}[/tex] x + 13 ← in slope- intercept form
The equation of a line in standard form is
Ax + By = C ( A is a positive integer and AB, C are integers )
multiply all terms in the slope-intercept form by 3
3y = x + 39 ( subtract 3y from both sides )
0 = x - 3y + 39 ( subtract 39 from both sides )
x - 3y = - 39 ← in standard form
