Which equation demonstrates that nuclear fusion forms elements that are heavier than helium?

The answer would be ¹⁶₈O = ⁴₂ He ⇒ ²⁰₁₀ Ne
Just add the atomic masses (the top numbers together) and the protons (the bottom numbers) together.
Answer: The correct answer is Option b.
Explanation:
Nuclear fusion reaction is defined as the reaction in which two or more lighter atoms combine to form a heavier atom. The number of atoms formed in this reaction decreases from the given atoms.
Nuclear fission reactions is defined as the reaction in which heavier atoms splits into two or more lighter atoms. The number of atoms formed in this reaction increases from the given atoms.
For the given options:
Option a: This is a nuclear fusion reaction for the element lighter than helium. Hydrogen is lighter element than helium.
Option b: This us a nuclear fusion reaction for the element which is heavier than helium. Oxygen element is heavier than helium element.
Option c: This is a nuclear fission reaction. Uranium element is getting split into two or more lighter elements.
Option d: This is a nuclear fission reaction. Uranium element is getting split into two or more lighter elements.
Hence, the correct answer is Option b.