Answer: Option '2' is correct.
Step-by-step explanation:
Since we have given that
A six-sided number cube is rolled.
Let A be the event of getting the first number rolled was 3 .
Let B be the event of getting 4.
Probability of getting the first number rolled was 3 is given by
[tex]P(A)=\frac{6}{36}=\dfrac{1}{6}[/tex]
Probability of getting a 3 then a 4 is given by
[tex]P(A\cap B)=\frac{1}{36}[/tex]
so, our required probability is given by
[tex]P(B\mid A)=\frac{P(A\cap B)}{P(A)}=\frac{\dfrac{1}{36}}{\dfrac{1}{6}}=\dfrac{1}{6}[/tex]
Hence, Probability of getting a 3 and then a 4 given that the first number rolled was a 3 is [tex]\dfrac{1}{6}[/tex]
Therefore, Option '2' is correct.
Answer:Answer: Option '2' is correct. which is 1/6
Step-by-step explanation:took the test ang got it right
