The limiting reagent is H₂SO₄
calculation
Step 1 :write the equation for reaction
2 NaOH + H₂SO₄ → Na₂SO₄ + 2 H₂O
Step 2: use the mole ratio to determine the moles of product produced from each reactant
that is from equation above,
NaOH : Na₂SO₄ is 2 :1 therefore the moles of Na₂So₄
= 10.0 moles x 1/2 = 5.0 moles
H₂SO₄ :Na₂SO₄ is 1:1 therefore the moles of Na₂SO₄ is also = 3.50 moles
H₂SO₄ is the limiting reagent since it produces less amount of Na₂SO₄
