Answer:
[tex]\frac{40}{3}[/tex]
Step-by-step explanation:
Here a= 20, r = -1/2
Here, the absolute value of r is 1/2 which is less than 1. So, the series converges.
The sum of an infinite geometric series is given by
S = [tex]\frac{a}{1-r}[/tex]
Substituting the values in the above equation, we have
[tex]S = \frac{20}{1-(-1/2)} =\frac{20}{3/2} =\frac{40}{3}[/tex]
∴ The sum of the given infinite series is 40/3
