Respuesta :
Answer:
r>0 and V(r)>0
Step-by-step explanation:
Number one: There arent no negative volumes
Number two: There aren't Negative radi
Thus V(r) and r must be greater than one. I attach the graph V(r)=5 Pi r^2
The domain would be (0,infinity)
The range would be (0, infinity)

The domain of a function is [tex]$r \geq 0$[/tex] and range of a function is [tex]$V(r) \geq 0$[/tex].
How to find the domain and range of the function?
The formula for the volume of a cylinder with a height of 5 units is:
[tex]V(r)=5 \pi r^{2}$[/tex]
Where [tex]$\mathrm{r}$[/tex] is the radius of the cylinder and [tex]$\mathrm{r}$[/tex] cannot be in negative
Let [tex]$r \geq 0$[/tex] here, [tex]$\mathbf{r}$[/tex] is the independent variable and [tex]$\mathbf{V}(\mathbf{r})$[/tex] is the dependent variable by definition of domain and range.
The domain of the given function is: [tex]$r \geq 0$[/tex] or in the interval [tex]$=[0, \infty)$[/tex]
The range of the function [tex]$(\mathrm{V}(\mathrm{r}))$[/tex] is: [tex][0, \infty)$[/tex].
Therefore the correct answer is r > 0, V(r) > 0.
Learn more about the domain and range of this function
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