The formula for the volume of a cylinder with a height of 5 units is v(r)=5(3.14)r^2 where r is the radius of the cylinder. What is the domain and range of this function?

r < 0, V(r) < 0
r > 0, V(r) < 0
r < 0, V(r) > 0
r > 0, V(r) > 0

Respuesta :

Answer:

r>0 and V(r)>0

Step-by-step explanation:

Number one: There arent no negative volumes

Number two: There aren't Negative radi

Thus V(r) and r must be greater than one. I attach the graph V(r)=5 Pi r^2

The domain would be (0,infinity)

The range would be (0, infinity)


Ver imagen danielferreyra12

The domain of a function is [tex]$r \geq 0$[/tex] and range of a function is [tex]$V(r) \geq 0$[/tex].

How to find the domain and range of the function?

The formula for the volume of a cylinder with a height of 5 units is:

[tex]V(r)=5 \pi r^{2}$[/tex]

Where [tex]$\mathrm{r}$[/tex] is the radius of the cylinder and [tex]$\mathrm{r}$[/tex] cannot be in negative

Let [tex]$r \geq 0$[/tex] here, [tex]$\mathbf{r}$[/tex] is the independent variable and [tex]$\mathbf{V}(\mathbf{r})$[/tex] is the dependent variable by definition of domain and range.

The domain of the given function is: [tex]$r \geq 0$[/tex] or in the interval [tex]$=[0, \infty)$[/tex]

The range of the function [tex]$(\mathrm{V}(\mathrm{r}))$[/tex] is: [tex][0, \infty)$[/tex].

Therefore the correct answer is r > 0, V(r) > 0.

Learn more about the domain and range of this function

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Ver imagen anjithaka