The question is incomplete, here is the complete question.
Which metal will form a compound with the general formula [tex]M_2CO_3[/tex] when it combines with a carbonate ion
A. Beryllium
B. Aluminum
C. Calcium
D. Lithium
Answer: The metal that will form the given compound is lithium.
Explanation:
We are given:
A general chemical formula of carbonate, which is [tex]M_2CO_3[/tex]
The given compound is an ionic compound.
Carbonate is a polyatomic ion having chemical formula [tex]CO_3^{2-}[/tex]
Metal ion has a charge of +1.
For the given options:
Option A: Beryllium is the 4th element of the periodic table having electronic configuration of [tex]1s^22s^2[/tex]
This element will loose 2 electrons to form [tex]Be^{2+}[/tex] ion.
Option B: Aluminium is the 13th element of the periodic table having electronic configuration of [tex]1s^22s^22p^63s^23p^1[/tex]
This element will loose 3 electrons to form [tex]Al^{3+}[/tex] ion.
Option C: Calcium is the 20th element of the periodic table having electronic configuration of [tex]1s^22s^22p^63s^23p^64s^2[/tex]
This element will loose 2 electrons to form [tex]Ca^{2+}[/tex] ion.
Option D: Lithium is the 3rd element of the periodic table having electronic configuration of [tex]1s^22s^1[/tex]
This element will loose 1 electron to form [tex]Li^{+}[/tex] ion.
Hence, the metal that will form the given compound is lithium.
