Answer: 23158.7 g
Explanation:
[tex]Q= n\times \Delta H[/tex]
Q= heat gained
[tex]\Delta H[/tex] = enthalpy of vaporization of water = 40.65 kJ/mol
1 mole of water requires 40.65 kJ of energy for vaporization.
40.65 kJ of energy is absorbed by = 1 mole of water
[tex]5.23\times {10^4}[/tex] kJ of energy is required by=[tex]\frac{1}{40.65}\times {5.23\times 10^4}=1286.6 moles[/tex]
[tex]n =\text{no of moles}=\frac{\text{given mass}}{\text{Molecular mass}}[/tex]
[tex]{1286.6mol}=\frac{given mass}{18gmol{-1}}[/tex]
given mass =23158.7 g
