You didn't specify which problems you needed and you are only allowed to submit three questions in one posting so I chose to solve 1, 3, and 5.
NOTES:
Inverse means to swap the x's and y's and solve for "y"
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1. Answer: y = [tex]\frac{2x+4}{3}[/tex]
Step-by-step explanation:
y = [tex]\frac{-4+3x}{2}[/tex]
swap: x = [tex]\frac{-4+3y}{2}[/tex]
2x = -4 + 3y
2x + 4 = 3y
[tex]\frac{2x+4}{3}[/tex] = y
3. Answer: y = -3(x - 1)
Step-by-step explanation:
y = [tex]-\frac{1}{3}x[/tex] + 1
swap: x = [tex]-\frac{1}{3}y[/tex] + 1
x - 1 = [tex]-\frac{1}{3}y[/tex]
-3(x - 1) = y
5. Answer: y = [tex]-\frac{4}{9}[/tex](x - 4)
Step-by-step explanation:
y = 4 - [tex]\frac{9}{4}x[/tex]
swap: x = 4 - [tex]\frac{9}{4}y[/tex]
x - 4 = [tex]-\frac{9}{4}y[/tex]
[tex]-\frac{4}{9}[/tex](x - 4) = y
