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what is the molarity of a solution prepared by dissolving 1.25g of HCL gas into enough water to make 30cm cube of solution?

Respuesta :

Willchemistry
30 cm³ / 1000 = 0.03 L

Molar mass HCl = 36.46 g/mol

number of moles:

mass of solute / molar mass

1.25 / 36.46 = 0.03428 moles

M = n / V

M = 0.03428 / 0.03

M = 1.14267 mol/L⁻¹

hope this helps!

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