Solve 2x2 + 3x = −8.

A) the quantity of negative 3 plus or minus 11 i all over 4
B) the quantity of negative 3 plus or minus i square root 55 all over 4
C) negative 3 plus or minus i square root 23
D) 3 plus or minus i square root 11

Respuesta :

Answer:

Final answer iis choice B) [tex]x=\frac{-3\pm i\sqrt{55}}{4}[/tex]

Step-by-step explanation:

[tex]2x^2 + 3x =-8[/tex]

[tex]2x^2 + 3x +8 = 0[/tex]

Compare with quadratic equation [tex]ax^2 + bx +c = 0[/tex], we get:

a=2, b=3, c=8

Now plug these values into quadratic formula:

[tex]x=\frac{-3\pm \sqrt{\left(3\right)^2-4\left(2\right)\left(8\right)}}{2\left(2\right)}[/tex]

[tex]x=\frac{-3\pm \sqrt{9-64}}{4}[/tex]

[tex]x=\frac{-3\pm \sqrt{-55}}{4}[/tex]

[tex]x=\frac{-3\pm i\sqrt{55}}{4}[/tex]

Hence final answer iis choice B) [tex]x=\frac{-3\pm i\sqrt{55}}{4}[/tex]