jtobin2003
contestada

Which of the following is a solution of x2 + 2x + 4?

A) −2 + two i times the square root of 3
B) 2 + two i times the square root of 3
C) 1 − i times the square root of 3
D) −1 + i times the square root of 3

Respuesta :

Answer:

option-D

Step-by-step explanation:

we are given

[tex]x^2+2x+4[/tex]

Let's assume it is equal to 0

[tex]x^2+2x+4=0[/tex]

We can use quadratic formula

Suppose, we are given quadratic equations as

[tex]ax^2+bx+c=0[/tex]

[tex]x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}[/tex]

we can compare and find a,b and c

a=1 , b=2 , c=4

now, we can plug values

and we get

[tex]x=\frac{-2\pm \sqrt{2^2-4\cdot \:1\cdot \:4}}{2\cdot \:1}[/tex]

now, we can simplify it

and we get

[tex]x=-1+\sqrt{3}i,\:x=-1-\sqrt{3}i[/tex]


alinakincsem

Answer:

The correct option is D) −1 + i times the square root of 3.

Step-by-step explanation:

We are given the following expression and we are to find the solutions for this quadratic expression:

[tex] x^2 + 2x + 4 [/tex]

Since we cannot factorize this so we will use the quadratic formula [tex]x = \frac{-b+-\sqrt{b^2-4ac} }{2a}[/tex] to solve it:

[tex] x [/tex] [tex] = [/tex] [tex] \frac{-(2) + -\sqrt{(2)^2-4(1)(4)} }{2 (1) } [/tex]

[tex] x [/tex] [tex] = [/tex] [tex] -1 + \sqrt {3i} , -1 - \sqrt {3i} [/tex]

Therefore, from the given answer options the correct option is D) −1 + i times the square root of 3.

Otras preguntas