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The area of the indoor sports exhibition is shown below. Use the following formulae:

Perimeter of a rectangle = 2l + 2w

Circumference of a circle = πd, π= 3.14

Area of a rectangle = lw

Area of a circle = πr


What is its perimeter? m

What is its area? m2

The area of the indoor sports exhibition is shown below Use the following formulae Perimeter of a rectangle 2l 2w Circumference of a circle πd π 314 Area of a r class=

Respuesta :

Answer:

Area: 3098 m^2

Perimeter: 356 m

Step-by-step explanation:

AREA

First find the area of the indoor sports park. Start by finding the area of the two rectangles using length times width (as shown in the first attachment).

Find the area of the half circle by finding the area of a circle ([tex]\pi r^2[/tex]) then dividing by 2.

Rect. 1 + Rect. 2 + Circle = Area

2244 + 400 + 908 (div'd by 2) = 3098 m^2

PERIMETER

Don't know what happened to the image but you get the idea.

The perimeter of the rectangles were found by adding up all the side lengths, and the perimeter (circumference) of the circle was found by using [tex]2\pi r[/tex].

Rect. 1 + Rect. 2 + Circle = Perimeter

202 + 100 + 107 (div'd by 2) = 355.5 (or 356) m

Ver imagen lily9211
Ver imagen lily9211