Respuesta :
[tex]speed = distance \div time[/tex]
Since the sound travels from the submarine to the object AND back, it actually travelled 3625x2=7250m.
[tex]7250 \div 5 = 1450[/tex]
Speed of sound: 1450m/s
distance of d object frm submarine = 3625m
time taken = 5/2
then speed = 3625/5/2. (speed = distance /time)
=> 1450m/s
seldon.
time taken = 5/2
then speed = 3625/5/2. (speed = distance /time)
=> 1450m/s
seldon.