Respuesta :
Answer: [tex]\bold{\dfrac{s^4-3s^3-2s+2}{(s-1)(s-1)(s-3)}}[/tex]
Step-by-step explanation:
Factor both denominators to see which factors are missing from each denominator. Then multiply both fractions so they have the same LCD.
[tex]\dfrac{s^3}{s^2-2s+1}+\dfrac{-2}{s^2-4s+3}[/tex]
[tex]=\dfrac{s^3}{(s-1)(s-1)}+\dfrac{-2}{(s-1(s-3)}[/tex]
[tex]=\dfrac{s^3}{(s-1)(s-1)}\bigg(\dfrac{s-3}{s-3}\bigg)+\dfrac{-2}{(s-1(s-3)}\bigg(\dfrac{s-1}{s-1}\bigg)[/tex]
[tex]=\dfrac{s^4-3s^3-2s+2}{(s-1)(s-1)(s-3)}[/tex]
Answer:
s⁴-6s³+12s²-10s+3
Step-by-step explanation:
s³/(s²-2s+1) - 2/(s²-4s+3)
The denominators are (s²-2s+1) and (s²-4s+3). Since one is not a multiple of the other, the least common denominator will be their product.
(s²-2s+1)(s²-4s+3) = s⁴-4s³+3s²-2s³+8s²-6s+s²-4s+3
= s₄ +(-4s³-2s³)+(+3s²+8s²+s²)+(-6s-4s)+3
= s⁴-6s³+12s²-10s+3