[tex] - 2 \: = \: \frac{2x \: + \: 1}{6x \: + \: 3} [/tex]
Multiplying and Dividing R.H.S. by 3, we get,
[tex] - 2 \: = \: \frac{1}{3} \: \times \: \frac{6x \: + \: 3}{6x \: + \: 3} [/tex]
or,
[tex] - 2 \: = \: \frac{1}{3} [/tex]
Which is not possible, so, no such equation can exist.
Hence, the answer is (C) as the denominator becomes 0, which doesn't make sense, as it is an Indeterminate form.